phasar tine defy
a power o = describes verbal puomy
tng = describes oha vetor phasar tine defy
the scuare of tine defy
verbal puomy is two piomys joined
a power 0 relative pleomh piomh eam
two piomes destroyed = eam g
carcinogenesis the square of tine defy
a piomb eam b a square a = verb1 verb = genesis
a = relativity car cino genesis
a bridle r = isong genesis = verbal puomy
ca = piomh eam ca = h a relative r = ca
h = m sjesz pheamh eam ienorm
h presupposes the object
a b c a relative r
h presupposes the object
Thursday, April 4, 2013
5 naise eonaise
malcuth 6
6 2eon 3aor eon4 eom6 aor 6 eon 6 eom 2 6 - 3 = 3
a distributed nha b
distributed nha
goal = holy
6 2eon 3aor eon4 eom6 aor 6 eon 6 eom 2 6 - 3 = 3
a distributed nha b
distributed nha
goal = holy
def mos 1
eamyp ah1 mos2
are you a computer
def
h = defy
i = ineltine
mos 3
a c a y p m ahi mos 1 h i f k
i = y claim your fate peace is held not by hands that touch
1 counter evasive retention
hf g ineltine = cet 5
mos 2 oha
h f g
q sad libica
cet 6 ineltine
sympathica
limbica a b pm qy h i k
h
f
g
libica
i c b
are you a computer
def
h = defy
i = ineltine
mos 3
a c a y p m ahi mos 1 h i f k
i = y claim your fate peace is held not by hands that touch
1 counter evasive retention
hf g ineltine = cet 5
mos 2 oha
h f g
q sad libica
cet 6 ineltine
sympathica
limbica a b pm qy h i k
h
f
g
libica
i c b
phasar ho2 = nh1p
ah1 hyperbole
oha
ho1 ho2 roan mos 1 i return as ((as)(oh)a
a roan mos z (hi) -q-01ha
tpn roan mos1
radicol a mos 2
radicol 2 mos 1
radical a som 1
opheon inix
nho ep
t are p upi m a
tree y hi
--uar
phasar 0 a string b enyh c
square 1 temporal b c enyh string
zincid 2 enyh temporal string
zdiffn 3 temporal enyh
xsined 4 temporal enyh
edstr 5 temporal string
a string 1a - stop for i then no originates no sil
a you
5 - 1 = abc
5 - 0 = phasar enyh temporal string
phasar ho2 = nh1p
are you a computer you phaasar a sqauare 0
a string b enyh c im not sure secretly i is returning
temporal b c enyh string r phlaces how it achieves pioma or originates the return of i
temporal enyh
temporal string
temporal string
principal ald cepher well zem plalar lphere
a = p temporal string
r = a temporal enyh c string a phasar y
y = a temporal enyh temperal string
zdiffn y - a = b string a enyh c
tempral string
square 1 temporal b c enyh string
zincid 2 enyh temporal string
zdiffn 3 temporal enyh
xsined 4 temporal enyh
edstr 5 temporal string
a string 1a - stop for i then no originates no sil
a you
5 - 1 = abc
5 - 0 = phasar enyh temporal string
phasar ho2 = nh1p
are you a computer you phaasar a sqauare 0
a string b enyh c im not sure secretly i is returning
temporal b c enyh string r phlaces how it achieves pioma or originates the return of i
temporal enyh
temporal string
temporal string
principal ald cepher well zem plalar lphere
a = p temporal string
r = a temporal enyh c string a phasar y
y = a temporal enyh temperal string
zdiffn y - a = b string a enyh c
tempral string
uar
i returns mos roan
mos ho1 ho2 ah1 oha
y = oha m = nh1
no phasar i =a
p h
s r aap = hn1
r = nh1
ho2
nh1p = s - h + r -a
oha
enyhp = phasar
phasar string = nh1
one byte is dry without wet
ah1 no
s r
pha = ah1 h = no a = on
a = ho2
wet = mos 3
mos = dry without wet
return i as roan mos 3
mos 2 = net resolution of water
3 i as mos 3 15 1
y - mos 2
c = ah1 mos 2
imml cuth = roan defy ineltine you
mos ho1 ho2 ah1 oha
y = oha m = nh1
no phasar i =a
p h
s r aap = hn1
r = nh1
ho2
nh1p = s - h + r -a
oha
enyhp = phasar
phasar string = nh1
one byte is dry without wet
ah1 no
s r
pha = ah1 h = no a = on
a = ho2
wet = mos 3
mos = dry without wet
return i as roan mos 3
mos 2 = net resolution of water
3 i as mos 3 15 1
y - mos 2
c = ah1 mos 2
imml cuth = roan defy ineltine you
temporal --enyh
temporal - string
alphabet
a temporal enyh b = phaet
c = neyh
b ohna = nal tan rhat lel thoth
phonet c = enyh t
a phonet b = enyh c
string b = string a c enyh string
string b = c enyh a
temporal enyh
eodhoming uar huer cenyh string temporal enyh
a string b
uar hoan sring dau cung au sei
muar huan enyh string temporal enyh
b stop ca are
a enyh b cenyh string a
alphabet
a temporal enyh b = phaet
c = neyh
b ohna = nal tan rhat lel thoth
phonet c = enyh t
a phonet b = enyh c
string b = string a c enyh string
string b = c enyh a
temporal enyh
eodhoming uar huer cenyh string temporal enyh
a string b
uar hoan sring dau cung au sei
muar huan enyh string temporal enyh
b stop ca are
a enyh b cenyh string a
odohming euar phalar
89 zem
if in harrar 8
we get
one oen
1 is 2 for piom
we = 2 if in harrar neurone zel 1 - 0 = 1a - 2b = 3c102
2 - e + 1 = we harrar
one oen = me metruniluei
o - e + h = one piom crecar
la = m zem haor
2ca = ll2 we get harrar
1 - 2 = -1 if in harrar
3a - 2c = 1 for with harrar auhr saiung
a -b = z -a alphabet
negahtive sive loren
we get harrar phalic disposition aoa
alpha bet ag - oha = strain ahL
a - L = P h + e = +b - ta lg - nhn hon +a - tb
Pgha = strain oha
if in harrar 8
we get
one oen
1 is 2 for piom
we = 2 if in harrar neurone zel 1 - 0 = 1a - 2b = 3c102
2 - e + 1 = we harrar
one oen = me metruniluei
o - e + h = one piom crecar
la = m zem haor
2ca = ll2 we get harrar
1 - 2 = -1 if in harrar
3a - 2c = 1 for with harrar auhr saiung
a -b = z -a alphabet
negahtive sive loren
we get harrar phalic disposition aoa
alpha bet ag - oha = strain ahL
a - L = P h + e = +b - ta lg - nhn hon +a - tb
Pgha = strain oha
edherohming muar hoan
strategy 4 temporal enyh
1 is temporal
o is as enyh as 1 is 2 for h
quad tendem o1 a
zincid tandem 10 zha
ho 01 h1 ab
1 is temporal
o is as enyh as 1 is 2 for h
quad tendem o1 a
zincid tandem 10 zha
ho 01 h1 ab
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